Questions
A graph of the square of the velocity against the square of the acceleration of a given simple harmonic motion is
a
b
c
d
detailed solution
Correct option is D
x=Asinωt v=dxdt=Aωcosωt=ωA2−x2a=dvdt=−Aω2sinωt=dvdt=−ω2x But x=−aω2∴ v=ωA2−a2ω4 or v2=ω2A2−a2ω4Talk to our academic expert!
Similar Questions
The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax
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