Q.

Graph of v2 Vs x2 for a particle executing SHM is

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a

Straight line with positive slope

b

Circle

c

Ellipse

d

Straight line with negative slope

answer is D.

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Detailed Solution

v=ωA2−x2⇒v2=ω2A2−ω2x2 Let v2=Y and x2=X So, Y=ω2A2−ω2XThis is of the form Y = mX + c  (equation of a straight line), where  c=ω2A2 and  slope, m=−ω2 .
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