Second law

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Question

Gravels are dropped on a conveyor belt at a rate of 0.5 kg/s. The extra force required in newtons to keep the belt moving at 2 m/s is

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Solution

$\begin{array}{l} t h r u s t f o r c e F = v_{r} \frac{d m}{d t} \\ = 2 \times 0.5 \\ = 1 N \end{array}$

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