Gravitational acceleration on the surface of the planet is 811g, where g is the acceleration due to gravity on the surface of earth. The average mass density of the planet is 2 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 kms-1, then find the escape speed on the surface of the planet (in kms-1).
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answer is 4.
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Detailed Solution
We know that, g=GMR2=43πGMρ∴gpge=RpρpReρe also ve=2gR∴vepvee=gpRpgeRe=gpge⋅gpρegeρp=gpgeρeρp=8112=411∴ vrp=411vee=411(11)=4kms−1