Questions
The gravitational field due to a mass distribution is in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is
detailed solution
Correct option is D
Gravitational field=E=-dVdx ⇒dV=-Edx ⇒∫dV=-∫Edx Gravitational potential =∫x∞Edx=∫x∞Kx3dx=K∫x∞x-3dx=K x−3+1−3+1x∞=−K2x2x∞=−K2(∞)2-−K2(x)2=0-K2x2=K2x2∵∫xndx=xn+1n+1+CTalk to our academic expert!
Similar Questions
Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is
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