The gravitational potential energy of a body of mass ‘m’ at the earth’s surface −mgRe . Its gravitational potential energy at a height Re from the earth’s surface will be (Here Re is the radius of the earth)

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−2 mgRe

2 mgRe

12mgRe

−12mgRe

answer is D.

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Detailed Solution

ΔU=U2−U1=mgh1+hRe=mgRe1+ReRe=mgRe2⇒U2−−mgRe=mgRe2⇒U2=−12mgRe

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