In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of mass m straight down with a speed u. When the ball reaches the floor, the distance of the man above the floor will be

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h1+mM

1+Mmh

mMh

answer is A.

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Detailed Solution

Centre of mass will remain at height h. ∴ hCM=m×0+MHm+M=h∴ H=h1+mM

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