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Q.

A ground to ground projectile is at point A at t=T3, is  at point B at t=5T6 and reaches the ground at t = T. The difference in heights between points A and B is gT26x. Find value of x.

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answer is 4.

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Detailed Solution

T=2uyg∴uy=gT2     hA=uytA−12gtA2=uy2uy3g−12g2uy3g2=49u2yg=49ggT22=gT29hB=uy59×2uyg−12×g×56×2uyg2=518uy2g=518ggT22=512gT2∴ hA−hB=gT224.
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