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Q.

The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is

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a

3.4eV

b

6.8eV

c

10.2eV

d

Zero

answer is C.

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Detailed Solution

Excitation energy is defined as the energy required to take the electron from ground level orbit to any higher order orbit (i.e., n = 2,3, 4...).Given, ground state energy of hydrogen atom E1 = -13'6 eVEnergy of electron in first excited state (i.e., n = 2)E2=−13.622eVTherefore. excitation energyΔE=E2−E1=−13.64−−136=−3.4+13.6=10.2eV
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