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A gun applies a force F on a bullet which is given by F=100-0.5×105tN. The bullet emerges out
with speed 400 m/s. Then, find out the impulse exerted till force on bullet becomes zero. [AIIMS 2019] 

a
0.2 N-s
b
0.3 N-s
c
0.1 N-s
d
0.4 N-s

detailed solution

Correct option is C

Force applied by gun,  F = (100-0.5×105t)NSpeed of bullet, v = 400 m/sWhen F = 0, then 100 - 0.5 X 105 t = 0⇒ t = 2×10-3s Impulse, I=∫Fdt=∫02×10-3100-0.5×105tdt=100t-0.5×105·t2202×10-3=100×2×10-3-0.5×1052×4×10-6-0=0.2-0.1=0.1 N-s

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