First slide

Projection Under uniform Acceleration

Question

A gun fires two bullets at 60^o at 30^o with horizontal. The bullets strike at some horizontal distance. The ratio of maximum height for the two bullets is in the ratio

Easy

A

2 : 1
B

3 : 1
C

4 : 1
D

1 : 1

Solution

The bullets are fired at the same initial speed
$\begin{array}{l} \frac{h}{h^{'}} = \frac{u^{2} \sin^{2} 60^{\circ}}{2 g} \times \frac{2 g}{u^{2} \sin^{2} 30^{\circ}} = \frac{\sin^{2} 60^{\circ}}{\sin^{2} 30^{\circ}} \\ = \frac{(\sqrt{3} / 2)^{2}}{(1 / 2)^{2}} = \frac{3}{1} \end{array}$

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