A gun of mass $$20$$ kg has bullet of mass $$0.1$$ kg in it. The gun is free to recoil $$804$$ J of recoil energy are released on firing the gun. The speed of bullet (ms-1) is

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Here, $$m1=20kg$$         $$m2=0.1kgwhere$$, $$v1$$ $$=$$ velocity of recoil of gunand      $$v2$$ $$=$$ velocity of bullet.As,        $$m1v1=m2v2$$           $$($$∵momentum is $$conserved)$$                         $$v1=m2m1v2=0.120v2=v2200Recoil$$ energy of gun $$=12m1v12=12$$×$$20v22002$$                                    $$804=10v224$$×$$104=v224$$×$$103$$                                    $$v2=804$$×$$4$$×$$103ms$$−$$1$$

A gun of mass 20 kg has bullet of mass 0.1 kg in it. The gun is free to recoil 804 J of recoil energy are released on firing the gun. The speed of bullet (ms^-1) is

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A gun of mass 20 kg has bullet of mass 0.1 kg in it. The gun is free to recoil 804 J of recoil energy are released on firing the gun. The speed of bullet (ms-1) is

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A gun of mass 20 kg has bullet of mass 0.1 kg in it. The gun is free to recoil 804 J of recoil energy are released on firing the gun. The speed of bullet (ms^-1) is