A gun of mass M fires a bullet of mass m with a velocity v relative to the gun. The average force required to bring the gun to rest in 1 sec is
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a
2MmvM+m
b
Mmv2(M+m)
c
3Mmv2(M+m)
d
Mmv(M+m)
answer is D.
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Detailed Solution
F=mMv(M+m)t =mMv1(M+m) Assume that velocity of the bullet is v2 and velocity of the gun is v1then M V1=m V2.........1 GIVEN VREL=v=V2+V1.........2 force required to hold the gun =F=M V1t given t=1 F=M V1.........3 FROM 1,2 and 3 F= M m vM+m