First slide

Projection Under uniform Acceleration

Question

A gun mounted on the top of a moving truck is aimed in the backward direction at an angle of 30⁰ to the vertical. If the muzzle velocity of the bullet is 4 ms^-1, the value of speed of the truck that will make the bullet come of out vertically is

Moderate

A

1ms^-1
B

$2 \sqrt{3} m s^{- 1}$
C

0.5ms^-1
D

2ms^-1

Solution

Horizontal component of velocity of the bullet after firing should be zero .
Therefore v- 4 sin $30^{0} = 0$ $\Rightarrow v = 2 m / s$

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