A gun mounted on the top of a moving truck is aimed in the backward direction at an angle of 300 to the vertical. If the muzzle velocity of the bullet is 4 ms-1, the value of speed of the truck that will make the bullet come of out vertically is
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a
1ms-1
b
23 ms-1
c
0.5ms-1
d
2ms-1
answer is D.
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Detailed Solution
Horizontal component of velocity of the bullet after firing should be zero .Therefore v- 4 sin 300 = 0 ⇒v = 2 m/s