A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atom is $8.8 \times 10^{10} C {kg}^{- 1}$ What is the mass of the electron? Given, charge of the electron $= 1.6 \times 10^{- 19} C$

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We know that Magnetic moment $$M=iA$$ Where, $$i=ev2$$$$π$$r,$$A=$$π$$r2$$&$$M=ev2$$$$π$$r×π$$r2$$⇒$$M=$$ evr $$2$$ and angular momentum Dividing Eq. (i) by Eq. (ii), we $$getML=e2m$$ where $$M/L=gyromagnetic$$ ratio. Given, $$ML=8.8$$×$$1010C/kg$$,$$e=1.6$$×$$10$$−$$19Cm=e2ML=1.6$$×$$10$$−$$102$$×$$8.8$$×$$1010=888$$×$$10$$−$$29=111$$×$$10$$−$$29kg$$

A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atom is $8.8 \times 10^{10} C {kg}^{- 1}$ What is the mass of the electron? Given, charge of the electron $= 1.6 \times 10^{- 19} C$

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A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atom is 8.8×1010Ckg−1 What is the mass of the electron? Given, charge of the electron =1.6×10−19C

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A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atom is $8.8 \times 10^{10} C {kg}^{- 1}$ What is the mass of the electron? Given, charge of the electron $= 1.6 \times 10^{- 19} C$