Hailstone at 0ºC falls from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt ? (Given: g=10m/s2,Lt=3.3×105

Initial potential energy of hailstone = MghJust before reaching the ground this potential energy will convert into kinetic energy.So, required kinetic energy which converts to heat energy = MghLet m mass of hailstone melts, so Mgh = =mL⇒mM=ghL=10×10003.3×105=133