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The half life for the $α$ decay of uranium $_{92} u^{238}$ is $4.47 \times 10^{9}$ yr. if a rock contains sixty percent of its original $_{92} u^{238}$ atoms, its age is $[\log 6 = 0.778; \log 2 = 0.3]$

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3.3×109Y

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detailed solution

Correct option is A

Here, T=4.47×109yr NN0=60100=(12)n or 2n=106 nlog2=log10−log6=1−0.778=0.222 n=0.222log2=0.2220.3=0.74 t=nT=0.74×4.47×109yr =3.3×109yr

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The half life for the α decay of uranium 92u238 is 4.47×109 yr. if a rock contains sixty percent of its original 92u238 atoms, its age is [log6=0.778;log2=0.3]

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Ready to Test Your Skills?

free study material

The half life for the $α$ decay of uranium $_{92} u^{238}$ is $4.47 \times 10^{9}$ yr. if a rock contains sixty percent of its original $_{92} u^{238}$ atoms, its age is $[\log 6 = 0.778; \log 2 = 0.3]$