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Q.

The half life for the α  decay of uranium 92u238  is 4.47×109  yr. if a rock contains sixty percent of its original 92u238 atoms, its age is [log6=0.778;log2=0.3]

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a

3.3×109Y

b

6.6×109Y

c

1.2×108Y

d

5.4×107Y

answer is A.

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Detailed Solution

Here, T=4.47×109yr NN0=60100=(12)n or 2n=106 nlog2=log10−log6=1−0.778=0.222 n=0.222log2=0.2220.3=0.74 t=nT=0.74×4.47×109yr =3.3×109yr
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