Half life of a radio active element is 1200 yrs. It m0 gm of radio active element existing now, m0/4 gm will remain radio active after

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600 years

4800 years

2400 years

2800 years

answer is C.

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Detailed Solution

NN0=1(2)t/T⇒m0/4m0=1(2)t/T⇒1(2)2=1(2)t/T⇒t/T=2⇒t=2×1200 years = 2400 years

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