The half life of a radio active substance is 10 days. This means that
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a
The substance completely disintegrates in 20 days.
b
The substance completely disintegrates in 40 days.
c
1/8 part of the total number of active nuclei of the substance will be left infact at the end of 40 days.
d
7/8 th part of the total number of active nuclei of the substance disintegrates in 30 days.
answer is D.
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Detailed Solution
After 30 days (i.e. 3 half lives) number of active nuclei left is given by N=N023T3=N08.So total number of nuclei disintegrates in 30 days =N0−N08=78N0