First slide

Radio activity

Question

The half life of a radioactive element which has only $\frac{1}{32}$ of its original mass left after a lapse of 60 days is

Easy

A

12 days
B

32 days
C

60 days
D

64 days

Solution

$\frac{N_{0}}{32} = N_{0} {(\frac{1}{2})}^{60 / T} \Rightarrow 5 = \frac{60}{T} \Rightarrow T = 12 days$

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