The half life of radioactive Radon is 3.8 days. The time at the end of which 1/20th of the Radon sample will remain undecayed is(Given log10 e = 0.4343)
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a
3.8 days
b
16.5 days
c
33 days
d
76 days
answer is B.
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Detailed Solution
By the lormula N = Noe-λtGiven NN0=120 and λ=0.69313.8⇒20=e0.69313.8Taking 1og of both sides or log 20=0.6931 x t3.8log10eor 1.3010 =0.6931 x t x 0.43433.8 ⇒t=16.5 days