Questions
Half life of a radio-active substance is 20 minutes. The time between 20% and 80% decay will be
a
20 minutes
b
40 minutes
c
30 minutes
d
25 minutes
detailed solution
Correct option is B
We know NN0=12t/T1/2For 20% decay NN0=80100=12t1/20 .........(i)For 80% decay NN0=20100=12t2/20 .........(ii)Dividing (ii) by (i) 14=12t2-t120;on solving we get t2-t1=40 min.Talk to our academic expert!
Similar Questions
The half life period of a radioactive element X is same as the mean life time of another radioactive element Y. Initially both of them have the same number of atoms. Then
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