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Q.

Half life of a radio-active substance is 20 minutes. The time between 20% and 80% decay will be

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a

20 minutes

b

40 minutes

c

30 minutes

d

25 minutes

answer is B.

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Detailed Solution

We know NN0=12t/T1/2For 20% decay NN0=80100=12t1/20    .........(i)For 80% decay NN0=20100=12t2/20    .........(ii)Dividing (ii) by (i) 14=12t2-t120;on solving we get t2-t1=40 min.
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Half life of a radio-active substance is 20 minutes. The time between 20% and 80% decay will be