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Q.

Half lives of two radio active substance A & B are respectively 20 minutes & 40 minutes. Initially the samples of A & B have equal numbers of nuclei. After 80 minutes the ratio of remaining numbers of A & B nuclei is

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a

1 : 16

b

4 : 1

c

1 : 4

d

1 : 1

answer is C.

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Detailed Solution

NANB=(1/2)nA(1/2)nB=(1/2)4(1/2)2=14 ,  where nA  & nB  are number of half lives of samples A & B respectively. NA  & NB  are the remaining numbers of A & B after 80 minutes in this case.
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