Half lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially the sample of A and B have equal number of nuclei. After 80 minutes. the ratio of remaining number of A and B nuclei is
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a
1 : 16
b
4 : 1
c
1 : 4
d
1 : 1
answer is C.
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Detailed Solution
For 80 minutes, number of half-lives of sample A=nA=8020=4 and number of half-lives of sample B=nB=8040=2.Also by using N=N012n⇒N∝12n⇒NANB=2nB2nA=2224=14
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Half lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially the sample of A and B have equal number of nuclei. After 80 minutes. the ratio of remaining number of A and B nuclei is