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Q.

Half lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially the sample of  A  and  B  have equal number of nuclei. After 80 minutes. the ratio of remaining number of  A  and B nuclei is

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a

1 : 16

b

4 : 1

c

1 : 4

d

1 : 1

answer is C.

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Detailed Solution

For 80 minutes, number of half-lives of sample A=nA=8020=4 and number of half-lives of sample B=nB=8040=2.Also by using N=N012n⇒N∝12n⇒NANB=2nB2nA=2224=14
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