Half a mole of helium at 270C and at a pressure of 2 atmosphere is mixed with 1.5 mole of N2 at 770 C and at a pressure of 5 atmosphere so that the volume of the mixture is equal to the sum of their initial volumes. If the temperature of the mixture is 690C, its pressure in atmosphere is

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3.5

3.8

3.95

4.25

answer is B.

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Detailed Solution

PV = nRT V=nRTPFrom conservation of mole numbern1+n2=nn1+n2=PRTV1+V2n1+n2=PRTn1RT1P1+n2RT2P2n1+n2=PTn1T1P1+n2T2P20.5+1.5=2=PT0.5T1P1+1.5T2P22=P3420.53002+1.53505P = 3.8 atm

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