A half ring of radius ‘ r ’ has a linear charge density λ .The potential at the centre of the half ring is

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λ4ε0

λ4π2ε0r

λ4πε0r

λ4πε0r2

answer is A.

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Detailed Solution

potential due to small element ‘ p ’ at the centre V=∫dv=∫kλrdl=14πε0λr∫dldv=K⋅λdlr;=14πε0λrπr⇒λ4ε0

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