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Questions  

The half-life of Bi210 is 5 days. What time is taken by 78th part of the sample of decay?

a
3.4 days
b
10 days
c
15 days
d
20 days

detailed solution

Correct option is C

By using N=N012t/T; Where N=1-78N0=18N0 So 18N0=N012t/T⇒123=12t/5 ⇒t=15 days

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