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Half-life of a radioactive element is 10 days. The time during which quantity remains 1/10 of initial mass will be

a
100 days
b
50 days
c
33 days
d
16 days

detailed solution

Correct option is C

After three half-lives (i.e., 30 days) it remains 123=18 , so it will remain 110th , approximately in 33 days.

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