Q.

The half-life of a sample of a radioactive substance is 1 hour.If  8 x 1010 atoms are present at t = 0, then the number of atoms decayed  in the duration t = 2 hour to t = 4 hour will be

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a

2 x 1010

b

1.5 x 1010

c

Zero

d

Infinity

answer is B.

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Detailed Solution

N=N012tT1/2No. of atoms at t=2hr,N1=8 x 10101221=2 x 1010No. of atoms at t=4hr, N2=8 x 10101241=12 x 1010∴No. of atoms decayed in given duration =2-12 x 1010=1.5 x 1010
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