A hammer of mass 1 Kg having speed of 50 m/sec hits an iron nail of mass 200g. If the specific heat of iron is 0.105 cal/g0C and half the energy is converted into heat, the raise in the temperature of nail is

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Detailed Solution

W=JQ⇒12(12Mv2)=J.m.cΔθ ∆θ=Mv24Jmc⇒Δθ=7.10C

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