First slide
Second law
Question

A hammer of mass M strikes a nail of mass m with velocity of u m/s and drives it a metre into fixed block of wood. The average resistance of wood to the penetration of nail is

Moderate
Solution

Applying the conservation of momentum

mu=(M+m)v0

v0=MM+mu

The acceleration A can be obtained using the formula

v2=u2+2as

Here A is negative, y =0, u = v0 and s = a

02=v022Aa  or  A=v02/2a

 or A=Mm+M2u22a

Resistance =(M+m)A=M2(M+m)×u22a.

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