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Questions  

A hammer of mass M strikes a nail of mass m with velocity of u m/s and drives it a metre into a fixed block of wood. The average resistance of wood to the penetration of nail is

a
Mm+Mu22a
b
M2(m+M)2u22a
c
M2(m+M)u22a
d
M+mmu22a

detailed solution

Correct option is C

Applying the conservation of momentummu = (M + m)V0v0=Mm+MuThe acceleration A can be obtained using the formula v2=u2+2as. Here, we have0=v02−2Aa or A=v02/2a∴ A=Mm+M2u22aResistance = (M + m) A=M2(m+M)u22a.

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