First slide

Graphs

Question

The heat energy absorbed by a system in going through a cyclic process shown in figure is

Moderate

A

$10^{3} πJ$
B

$10^{2} πJ$
C

$10^{4} πJ$
D

$10^{7} πJ$

Solution

Work done = Area of P - V dig.
$\begin{array}{l} A = {πr}_{1} r_{2} = π \frac{(30 - 10)}{2} \times 10^{3} \times (\frac{30 - 10}{2}) \times 10^{- 3} \\ = π (10) \times 10 . J = 10^{2} πJ . \end{array}$

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