First slide

Thermodynamic processes

Question

Heat energy absorbed by a system in going through a cyclic process shown in figure is

Moderate

A

$10^{7} π J$
B

$10^{4} π J$
C

$10^{2} π J$
D

$10^{- 3} π J$

Solution

In cyclic process
$Δ U = 0$
So, $Δ Q = Δ W + 0$
$Δ Q = Δ W = Area of closed curve$
$Δ Q = {πr}_{1} r_{2} = π (\frac{30 - 10}{2}) \times 10^{- 3} (\frac{30 - 10}{2}) \times 10^{3} = 10^{2} π J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App