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Heat energy absorbed by a system in going through a cyclic process shown in figure is

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107πJ

104πJ

102πJ

10−3πJ

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detailed solution

Correct option is C

In cyclic process ΔU=0So, ΔQ=ΔW+0ΔQ=ΔW=Area of closed curveΔQ=πr1r2=π30-102×10-330-102×103=102πJ

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