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Q.

Heat energy absorbed by a system in going through a cyclic process shown in figure is

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a

107πJ

b

104πJ

c

102πJ

d

10−3πJ

answer is C.

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Detailed Solution

In cyclic process ΔU=0So, ΔQ=ΔW+0ΔQ=ΔW=Area of closed curveΔQ=πr1r2=π30-102×10-330-102×103=102πJ
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