Q.
Heat energy absorbed by a system in going through a cyclic process shown in figure is
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a
107πJ
b
104πJ
c
102πJ
d
10−3πJ
answer is C.
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Detailed Solution
In cyclic process ΔU=0So, ΔQ=ΔW+0ΔQ=ΔW=Area of closed curveΔQ=πr1r2=π30-102×10-330-102×103=102πJ
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