First slide

Heat Engine; Carnot Engine and refrigerator

Question

A heat engine is involved with exchange of heat of 1915 J, -40J, +125J and -QJ during one cycle achieving an efficiency of 50.0%. The value of Q is:

Moderate

A

400J
B

640J
C

980J
D

40J

Solution

$\begin{array}{l} % η = \frac{W_{n e t}}{Q_{a b s o r b e d}} \times 100 \\ F o r c l o s e d c y c l e \\ W_{n e t} = Q_{n e t} \\ \Rightarrow 50 = \frac{1915 - 40 + 125 - Q}{1915 + 125} \times 100 \\ \Rightarrow Q = 980 J \end{array}$

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