Questions
A heat engine is involved with exchange of heat of 1915 J, -40J, +125J and -QJ during one cycle achieving an efficiency of 50.0%. The value of Q is:
detailed solution
Correct option is C
%η=WnetQabsorbed×100 For closed cycle Wnet=Qnet ⇒50=1915−40+125−Q1915+125×100 ⇒Q=980JTalk to our academic expert!
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