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Q.

A heat engine receives 1600 calorie of heat energy from the source at 400K in each cycle. If the sink is at 300 K, the heat rejected per cycle to the reservoir is

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a

400 cal

b

400 J

c

1200 cal

d

1200 J

answer is C.

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Detailed Solution

efficiency of heat engine=η=1-T2T1=work done (W)heat given(Q1)=T1−T2T1T1=400K=temperature of source;T2=300k=temperature of sink;Q2=amount of heat rejected;Q1=1600calorie=amount of heat absorbed;w=work done;substitute in above equation,W1600=T1−T2T1W1600=400-300400⇒W=400CalorieHeat rejected to sink Q2=Q1−W=1600−400=1200Cal
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A heat engine receives 1600 calorie of heat energy from the source at 400K in each cycle. If the sink is at 300 K, the heat rejected per cycle to the reservoir is