Q.

Heat is flowing in steady state from temperature 100oC to temperature 0oC  through a rod of length l, cross sectional area A and thermal conductivity K at a rate Q. When another rod of length 2l, cross-sectional area A and thermal conductivity K/2 is joined end to end to the above rod to make a composite rod of length 3l whose ends are maintained at 100oC and 0oC, rate of heat conduction at steady state is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

2Q5

b

Q5

c

3Q5

d

4Q5

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For the first rod, thermal resistance R=lKA=100-0QFor the second rod, thermal resistance R'=2lK/2A=4lKA=4RSo equivalent thermal resistance Re=R+R'=R+4R=5R∴Q'=100-0Re=1005R=15 x Q
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon