Heat is flowing through two cylindrical rods of the same material. The diameters of the rods are in the ratio $$1$$ : $$2$$ and the lengths in the ratio $$2$$ : $$1$$. If the temperature difference between the ends is same, then ratio of the rate of flow of heat through them will be

Question

Infinity Learn · Accepted Answer

$$dQdt=KA$$Δ$$TL=K$$π$$(D/2)2$$ΔTL ∴ $$(dQ/dt)1(dQ/dt)2=K$$$$π$$$$D1/22$$ΔT×$$L2L1$$×K$$π$$$$D2/22$$Δ$$T=D12$$×$$L2D22$$×$$L1=14$$×$$12=18$$ or       $$(dQ/dt)1$$:$$(dQ/dt)2=1$$:$$8$$

Heat is flowing through two cylindrical rods of the same material. The diameters of the rods are in the ratio 1 : 2 and the lengths in the ratio 2 : 1. If the temperature difference between the ends is same, then ratio of the rate of flow of heat through them will be

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