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Specific heat and degrees of freedom

Question

Heat Q=32RT is supplied to 4 moles of an ideal diatomic gas at temperature T, which remains constant. Number of moles of the gas dissolved into atoms is_________.

Moderate
Solution

Let x moles of diatomic gas be associated. x moles of diatomic gas become 2x moles of a monatomic gas after dissociation. Internal energy of n moles of an ideal gas

=32nRT for monatomic gas

Internal energy of n moles of an ideal gas

=52nRT(for diatomic gas)

So. [Internal energy of 2x moles of a monatomic gas + internal energy of (4 - x) moles of a diatomic gas = internal energy of 4 moles of a diatomic gas

=32RT (given)

(2x)3RT2+(4x)52RT(4)52RT=32RT

On solving, x = 3 moles.



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