A heavy ball is suspended from the ceiling of a motor car through a light string. A transverse pulse travels at speed of $60 c m / \sec$ on the string when the car is at rest and $62 c m / \sec$ when the car accelerates on a horizontal road. The acceleration of the car is _________ $m / \sec^{2}$ .

Question

Infinity Learn · Accepted Answer

Initially , T $$=$$ mg Finally , $$T1=mg2+ma2=mg2+a2$$  Given   : V $$=$$ $$60$$ $$cm/$$$$sec$$ ,  $$V1=62$$ $$cm/$$$$sec$$  We know, $$V=T$$μ ∴$$V1V=T1T$$ ⇒$$6260=mg2+a21/2mg$$ ⇒$$1+260=1+a2g21/4$$ ⇒$$1+1304=1+a2g2$$ ⇒$$1+430=1+a2g2$$ ⇒$$a2=215g2$$ ⇒$$a=215$$×g ⇒$$a=3.65$$ $$m/sec2$$

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A heavy ball is suspended from the ceiling of a motor car through a light string. A transverse pulse travels at speed of $60 c m / \sec$ on the string when the car is at rest and $62 c m / \sec$ when the car accelerates on a horizontal road. The acceleration of the car is _________ $m / \sec^{2}$ .

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Travelling wave

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A heavy ball is suspended from the ceiling of a motor car through a light string. A transverse pulse travels at speed of 60 cm/sec on the string when the car is at rest and 62 cm/sec when the car accelerates on a horizontal road. The acceleration of the car is _________m/sec2.

Initially , T = mg Finally , T1=mg2+ma2=mg2+a2 Given : V = 60 cm/sec , V1=62 cm/sec We know, V=Tμ ∴V1V=T1T ⇒6260=mg2+a21/2mg ⇒1+260=1+a2g21/4 ⇒1+1304=1+a2g2 ⇒1+430=1+a2g2 ⇒a2=215g2 ⇒a=215×g ⇒a=3.65 m/sec2

Ready to Test Your Skills?

free study material

A heavy ball is suspended from the ceiling of a motor car through a light string. A transverse pulse travels at speed of $60 c m / \sec$ on the string when the car is at rest and $62 c m / \sec$ when the car accelerates on a horizontal road. The acceleration of the car is _________ $m / \sec^{2}$ .