Questions

A heavy block of mass M is slowly placed on a conveyer belt moving with a speed v. The coefficient of friction between the block and the belt is µ. Through what distance will the block slide on the belt?

Remember concepts with our Masterclasses.

80k Users

60 mins Expert Faculty Ask Questions

v/µg

v2/µg

v/2µg

v2/2µg

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is D

Force of friction = µ M g∴Acceleration = µ gNow v2=u2+2asThe block will slide on the belt till its velocity becomes v.Hencev2=2μgs or s=v2/2μg.

Talk to our academic expert!

Create Your Own Test
Your Topic, Your Difficulty, Your Pace

Similar Questions

A skier starts from rest at point A and slides down the hill without turning or breaking. The friction coefficient is $μ$ . When he stops at point B, his horizontal displacement is s. What is the height difference between points A and B?

(The velocity of the skier is small, so that the additional pressure on the snow due to the curvature
can be neglected. Neglect also the friction of air and the dependence of $μ$ on the velocity of the skier.)

View solution