A heavy block of mass M is slowly placed on a conveyer belt moving with a speed v. The coefficient of friction between the block and the belt is µ. Through what distance will the block slide on the belt?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
v/µg
b
v2/µg
c
v/2µg
d
v2/2µg
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Force of friction = µ M g∴Acceleration = µ gNow v2=u2+2asThe block will slide on the belt till its velocity becomes v.Hencev2=2μgs or s=v2/2μg.