Questions
A heavy but uniform rope of length L is suspended from a ceiling. A particle is dropped from the ceiling at the instant when the bottom end is given a transverse wave pulse. Where will the particle meet the pulse?
detailed solution
Correct option is B
[ Step 1]:V=gh∴dhdt=gh h is the height travelled by the wave from the bottom of the rope.[ Step 2 ]:∴t=∫0h dhgh or t=2hg[Concept]: Now at the time of meeting[Step 3]: Time of fall of particle = time of wave pulse on reaching up to these[Step 4]: 2(L−h)g=2hg where L-h is the distance through which the body dropped falls.[Step 5]: ∴h=L3Similar Questions
A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 3.0 cm. Find the wave speed (in m/s).
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