A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120. If binding energy per nucleon for parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, then the energy released in the decay will be:
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a
200 MeV
b
–220 MeV
c
220 MeV
d
180 MeV
answer is C.
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Detailed Solution
Energy released = (B. E. of product – BE of reactant)= (80 × 7 + 120 × 8 – 200 × 6.5) = 220 MeV.