Q.

A heavy particle is attached to one end of a string 1m long whose other end is fixed at O. It is projected from its lowest position horizontally with a velocity V:

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a

If V2 > 5 g the particle will describe complete circular motion in the vertical plane

b

If V2 = 3.5 g the tension in the string will become zero after the string has turned through 120o

c

If V2 = 2 g, the tension in the string becomes zero the velocity of the particle also becomes zero

d

If V2 = g the velocity of the particle becomes zero after the string turns through 60°

answer is A.

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Detailed Solution

−mgl(1−cos⁡θ)=12mv2−12mu2    .......(i)T−mgcos⁡θ=mv2l                      ........(ii)V2=gl(2−3cos⁡θ) (a) θ=π,V2=5gl, hence true  (b) 3.5=2−3cos⁡θ,cos⁡θ=−12       ⇒A=120∘ hence true  (c) 2=2−3cos⁡θ,cos⁡θ=0,θ⇒π2, hence true  (d) 1=2−3cos⁡θ,cos⁡θ=13,θ>60∘, hence true
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