Q.

The height above surface of earth where the value of gravitational acceleration is one fourth of that at surface, will be-

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a

Re/4

b

Re/2

c

3Re/4

d

Re

answer is D.

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Detailed Solution

g′g=Rr2=14;Rr=12;r=2R  . Therefore height above the earth surface = 2R-R =R
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