At a height H from the surface of earth, the total energy of a satellite is equal to the potential energy of a body of equal mass at a height 3R from the surface of the earth(R = radius of the earth). The value of H is [EAMCET 2014]
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a
R
b
4R3
c
3R
d
R3
answer is A.
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Detailed Solution
We know that, the total energy of the satellite,E=-12GMemRAt a height H from the surface of the earth, the total energy of satellite,E=-12GMem(R+H) …(i)and the potential energy of the satellite,U=-GMem(R+3R)=-GMem4R …(ii)From given conditlon, E=U⇒-12·GMem(R+H)=-GMem4R⇒ 12R+2H=14R⇒2H=4R-2R⇒H=R