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The height at which the acceleration due to gravity becomes $\frac{g}{9}$ (where g = the acceleration due to gravity on the surface of the earth) in erms of R, the radius of the earth is :

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Correct option is C

gn=g1+hR2⇒g9=g1+hR2⇒1+hR=3⇒h=2R

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The height at which the acceleration due to gravity becomes g9 (where g = the acceleration due to gravity on the surface of the earth) in erms of R, the radius of the earth is :

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The height at which the acceleration due to gravity becomes $\frac{g}{9}$ (where g = the acceleration due to gravity on the surface of the earth) in erms of R, the radius of the earth is :