The height at which the value of acceleration due to gravity becomes 50% of that at the surface of the earth.(Radius of the earth =6400 km ) is
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a
2650
b
2430
c
2250
d
2350
answer is A.
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Detailed Solution
Acceleration due to graviy decreases by 50% means g'=g/2 g'=GM(R+h)2⇒g'=gR2R+h2=g1+hR2 ⇒g2=g1+hR2 ⇒2=1+hR2 ⇒2=1+hR ⇒hR=2-1=1.414-1=0.414 ⇒h=0.414×6400km=2649.6km