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The height at which the weight of a body become $\frac{1}{16} th$ , its weight on the surface of earth (radius R) is :

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detailed solution

Correct option is A

mgh=mg1+hR2⇒mg16=mg1+hR2⇒h=3R

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The height at which the weight of a body become 116th, its weight on the surface of earth (radius R) is :

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The height at which the weight of a body become $\frac{1}{16} th$ , its weight on the surface of earth (radius R) is :