First slide

Variation of g

Question

The height at which the weight of a body become $\frac{1}{16} th$ , its weight on the surface of earth (radius R) is :

Easy

A

3R
B

4R
C

5R
D

15R

Solution

${mg}_{h} = \frac{mg}{{(1 + \frac{h}{R})}^{2}} \Rightarrow \frac{mg}{16} = \frac{mg}{{(1 + \frac{h}{R})}^{2}} \Rightarrow h = 3 R$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App