Questions
The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t2) meter and x = 6t meter, where r is in seconds. The velocity of projection is:
detailed solution
Correct option is C
y = 8t - 5t2vy=dydt=8-10tx = 6tvx=dydt=6Velocity at any time ‘t’ v=vx2+vy2=62+8-10t2Velocity of projection (i.e., velocity at t = 0)= 62+82=10m/sTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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